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§13Class 10, Chapter 13

Statistics: Finding the 'typical' value in a pile of numbers

Extends mean, median and mode from single numbers to grouped data — the tools behind every average, ranking, and 'most popular' claim you've ever heard.

meanmodemedianΣfᵢxᵢcumulative frequencyogive

🧮13.1 - 13.2 Mean of Grouped Data

Dump your whole class's test scores into one pile and a measure of central tendency is the friend who looks at that mess and says, in one number, "here's roughly what's going on." You already know three such friends from Class IX — mean, median, and mode. This chapter teaches them to work with grouped data, where individual scores are bundled into class intervals like 10-25, 25-40, and so on, instead of listed one by one.

📸
Think of a school photo taken in rows.. Once students are grouped into rows for a photo, you can't measure each individual's exact height anymore — you can only estimate using the middle of each row. That 'middle of the row' is exactly what a class mark is.
Class mark = (Upper class limit + Lower class limit) / 2

Method 1: The Direct Method

For ungrouped data, mean = sum of observations ÷ number of observations. For grouped data, the class mark xᵢ stands in for every observation inside that class, and gets weighted by its frequency fᵢ.

x̄ = Σfᵢxᵢ / Σfᵢ
SET UPMarks of 30 students grouped into 10-25, 25-40, 40-55, 55-70, 70-85, 85-100 with frequencies 2, 3, 7, 6, 6, 6.
CLASS MARKSxᵢ = 17.5, 32.5, 47.5, 62.5, 77.5, 92.5.
MULTIPLYfᵢxᵢ = 35, 97.5, 332.5, 375, 465, 555.
SUMΣfᵢxᵢ = 1860, Σfᵢ = 30.
DIVIDEx̄ = 1860 / 30 = 62.
⚠️This 62 is an approximate mean, not exact — we assumed every observation in a class sits exactly at the class mark. Real data is rarely that tidy, but it's a fair, workable estimate.

🚀13.2 Assumed Mean & Step-Deviation Methods

When xᵢ and fᵢ are large numbers, direct multiplication turns tedious fast — like doing long multiplication by hand during a timed test. 😩 So we shrink the numbers first, do easy arithmetic, then scale back at the end. The final answer never changes; only the path to it gets shorter.

Method 2: Assumed Mean Method

Pick any class mark as an 'assumed mean' a — usually the middle one. Find how far every other xᵢ deviates from it: dᵢ = xᵢ − a. The true mean is then a plus the average deviation.

x̄ = a + Σfᵢdᵢ / Σfᵢ

Method 3: Step-Deviation Method

If the dᵢ values share a common factor (the class size h), shrink them further into uᵢ = (xᵢ − a) / h. It's like converting large rupee amounts into smaller unit-counts before adding — same total, friendlier numbers along the way.

x̄ = a + (Σfᵢuᵢ / Σfᵢ) × h
MethodFormulaBest used when
Directx̄ = Σfᵢxᵢ / Σfᵢxᵢ and fᵢ are small numbers
Assumed Meanx̄ = a + Σfᵢdᵢ / Σfᵢxᵢ and fᵢ are large
Step-Deviationx̄ = a + (Σfᵢuᵢ / Σfᵢ) × hdᵢ's share a common factor, or class sizes are unequal
No matter which class mark you pick as the assumed mean a, the arithmetic always lands on the same true mean. It's purely a computational shortcut, not a different method with a different answer — Activity 1 in the textbook proves this by trying several different values of a.

🏆13.3 Mode of Grouped Data

If mean is the 'average performer', mode is the 'crowd favourite' — the value that shows up most often. Think of the most-streamed song of the week: not necessarily the best song by every measure, just the one everyone's playing the most. 🎵

In grouped data we can't spot one exact repeated value, so we locate the modal class — the class interval with the highest frequency — and estimate a mode that lies somewhere inside it.

Mode = l + [(f₁ − f₀) / (2f₁ − f₀ − f₂)] × h
  • l = lower limit of the modal class
  • h = size of the class interval (assumed equal)
  • f₁ = frequency of the modal class
  • f₀ = frequency of the class before the modal class
  • f₂ = frequency of the class after the modal class
IDENTIFYFamily sizes 1-3, 3-5, 5-7, 7-9, 9-11 have frequencies 7, 8, 2, 2, 1 — highest is 8, so modal class = 3-5.
READ OFFl=3, h=2, f₁=8, f₀=7, f₂=2.
SUBSTITUTEMode = 3 + [(8−7)/(16−7−2)] × 2 = 3 + 2/7 = 3.286.
🎯Mean vs Mode isn't a competition — they answer different questions. In the marks example, mean was 62 but mode was 52: most students clustered a bit below average, while a handful of high scorers pulled the mean up.

🔗13.4 Cumulative Frequency & Median of Grouped Data

Median is the 'middle person in the queue' — exactly half the data lies below it, half above. For grouped data, we first build a cumulative frequency table: a running total, like a scoreboard that keeps adding up as each new class interval joins in.

TypeMeaning
Less than typeRunning total of frequencies UP TO the upper limit of each class
More than typeRunning total of frequencies FROM the lower limit of each class onward

To find the median class, locate the class whose cumulative frequency is the first to reach or exceed n/2.

Median = l + [(n/2 − cf) / f] × h
  • l = lower limit of the median class
  • n = total number of observations
  • cf = cumulative frequency of the class before the median class
  • f = frequency of the median class
  • h = class size
FIND n/251 girls' heights, n=51, so n/2 = 25.5.
BUILD cfCumulative frequencies: 4, 11, 29, 40, 46, 51 across the six classes.
LOCATE25.5 is first exceeded at cf=29 → median class = 145-150.
SUBSTITUTEl=145, cf=11, f=18, h=5 → Median = 145 + [(25.5−11)/18] × 5 = 149.03 cm.
📐Before using the mode or median formula, class intervals MUST be continuous. If given as 118-126, 127-135 (a gap of 1), convert to 117.5-126.5, 126.5-135.5, and so on, by subtracting/adding half the gap.

🧭13.5 Choosing the Right Measure — Summary

Three friends, three personalities. 🤝 Mean accounts for every observation, making it ideal for comparing overall performance — but it's easily dragged around by extreme values, like one billionaire skewing a neighbourhood's 'average income.'

Median ignores exactly how extreme the extremes are, just cares about the middle — perfect for things like typical wages. Mode answers 'what's most popular?' — ideal for favourite TV shows, best-selling shoe sizes, or the most-used vehicle colour.

3 × Median = Mode + 2 × Mean
🔑
This empirical relationship is a lifesaver in exams — given any two of the three measures, solve directly for the third instead of recomputing from raw data.
Question typeBest measure
Compare overall performance across groupsMean
Find a 'typical' value when extreme values existMedian
Find the most frequent / most popular valueMode